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  • 面向Java開發人員db4o指南:數組和集合

    發表于:2008-04-28來源:作者:點擊數: 標簽:javaJAVAJava開發指南
    關鍵字: 處理多樣性關系 舒適的家庭生活會導致一個或更多 “小人兒” 降臨到這個家庭。但是,在增加小孩到家庭中之前,先確保 Person 真正有地方可
    關鍵字:
     

    處理多樣性關系

    舒適的家庭生活會導致一個或更多 “小人兒” 降臨到這個家庭。但是,在增加小孩到家庭中之前,先確保 Person 真正有地方可住。給他們一個工作場所,或者還有一個很好的夏日度假屋。一個 Address 類型應該可以解決所有這三個地方。

    清單 1. 添加一個 Address 類型到 Person 類中

    package com.tedneward.model; 
    
    public class Address
    {
    public Address()
    {
    }
    
    public Address(String street, String city, String state, String zip)
    {
    this.street = street; this.city = city; 
    this.state = state; this.zip = zip; 
    }
    
    public String toString()
    {
    return "[Address: " + 
    "street=" + street + " " +
    "city=" + city + " " +
    "state=" + state + " " +
    "zip=" + zip + "]"; 
    }
    
    public int hashCode()
    {
    return street.hashCode() & city.hashCode() &
    state.hashCode() & zip.hashCode(); 
    }
    
    public boolean equals(Object obj)
    {
    if (obj == this)
    return this; 
    
    if (obj instanceof Address)
    {
    Address rhs = (Address)obj; 
    
    return (this.street.equals(rhs.street) &&
    this.city.equals(rhs.city) &&
    this.state.equals(rhs.state) &&
    this.zip.equals(rhs.zip)); 
    }
    else
    return false; 
    }
    
    public String getStreet() { return this.street; }
    public void setStreet(String value) { this.street = value; }
    
    public String getCity() { return this.city; }
    public void setCity(String value) { this.city = value; }
    
    public String getState() { return this.state; }
    public void setState(String value) { this.state = value; }
    
    public String getZip() { return this.zip; }
    public void setZip(String value) { this.zip = value; }
    
    private String street; 
    private String city; 
    private String state; 
    private String zip; 
    }

    原文轉自:http://www.kjueaiud.com

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