• <ruby id="5koa6"></ruby>
    <ruby id="5koa6"><option id="5koa6"><thead id="5koa6"></thead></option></ruby>

    <progress id="5koa6"></progress>

  • <strong id="5koa6"></strong>
  • 計算機英語:“與”函數

    發表于:2008-02-18來源:作者:點擊數: 標簽:計算機英語
    The AND Function The AND function can be illustrated by the fol lowing analogy. The members of group A are Bob, Charley, and Dick. Note that the names in this group combined by the conjunction“and”.That means group A equals the presence
    The AND Function   

      The AND function can be illustrated by the fol lowing analogy. The members of group A are Bob, Charley, and Dick. Note that the names in this group combined by the conjunction“and”.That means group A equals the presence of Bob and Charley and Dick. This may be symbolized as     
      A=B•C•D 
      A is true (group A is present) when B istrue(Bob is present),AND C is true (Charley is present).AND D is true (Dick is present). A is not trueif anv one (or more) of the members are absent.


      The circuit in Figure 6-2 can be used to producethe AND function of the above example. The lightindicates that group A is present only when all mcm-bers of the group are present. A logic circuit produc-ing the AND function is called an AND gate and issymbolized in Figure 6-3.


      Figure 6-4(a) shows the logic symbol for a twoinput AND gate. The function (A-B) is producedwhen A is true AND B is true. In order to show all ofthe conditions that may exist at the input and outputof a logic gate, truth tables are used. Because thereare two inputs and each input has two possible states(true and false),the number of possible conditions at, I,Ile nput would be 2 raised to the second power (22),or 4.The truth table for a two- input AND gate isshown in Figure 6-4(b) Note that condition 4 is theanly one in which all of the inputs are true so that theAND function is produced and a true output appears。


      AND gates may have two or more inputs.Figure0-5 shows a three-input AND gate and its truth tableOncs(I)and zcros(O) are used for the alucs of theN ariables.Because three variables are used. eight:onditions exist(23=8).Condition 8 is the onk onethat will produce a true output(I)because all of theinput variables are true(equal to I).

    原文轉自:http://www.kjueaiud.com

    老湿亚洲永久精品ww47香蕉图片_日韩欧美中文字幕北美法律_国产AV永久无码天堂影院_久久婷婷综合色丁香五月

  • <ruby id="5koa6"></ruby>
    <ruby id="5koa6"><option id="5koa6"><thead id="5koa6"></thead></option></ruby>

    <progress id="5koa6"></progress>

  • <strong id="5koa6"></strong>